# A projectile is shot at an angle of pi/4  and a velocity of  27 m/s. How far away will the projectile land?

${x}_{m} = 74 , 312 \text{ m}$
$\theta = \frac{\cancel{\pi}}{4} \cdot \frac{180}{\cancel{\pi}} = {45}^{o}$
${x}_{m} = \frac{{v}_{i}^{2} \cdot \sin 2 \theta}{g}$
${x}_{m} = \frac{{27}^{2} \cdot \sin \left(2 \cdot 45\right)}{9 , 81}$
${x}_{m} = \frac{729 \cdot 1}{9.81}$
${x}_{m} = 74 , 312 \text{ m}$