A projectile is shot at an angle of #pi/6 # and a velocity of # 5 m/s#. How far away will the projectile land?

1 Answer
Apr 24, 2017

2.2 m

Explanation:

To solve this kinematics problem, we have to consider motion in both the horizontal and vertical component. We then realise that the t value (time of flight) would be the same for both components.

Vertical component:

Given #u=5sin(pi/6)=2.5m/s#,
#v=-u=-2.5m/s#
and #a=-9.81m/(s^2)# ,
find t.

#v=u+at#
#t=(v-u)/a=(-2.5-2.5)/(-9.81)=0.5097s#

Horizontal component:

Given #t=0.5097s#
and #v=5cos(pi/6)=4.330m/s# ,
find d.

distance
= speed x time
= (4.330)(0.5097)
= 2.207 m

Thus, the projectile will land 2.2 m away.