Question

A projectile is shot at an angle of `pi/8` and a velocity of `6 m/s`. How far away will the projectile land?

Answer 1

`"2.6 m"`

Explanation:

Range of the projectile is given as

`"Range" = (u^2sin2theta) /g`

`"Range" = (("6 m/s")^2 sin(2 × π/8)) / ("9.8 m/s"^2) = "2.6 m"`