A projectile is shot from the ground at an angle of #(5 pi)/12 # and a speed of #3/5 m/s#. Factoring in both horizontal and vertical movement, what will the projectile's distance from the starting point be when it reaches its maximum height?
We're asked to find the distance from the launch point a particle is when it reaches its maximum height, given its initial velocity.
To do this, we can use the equations
to find the vertical and horizontal positions, respectively, when the particle is at its maximum height.
We realize that the instantaneous s
The time it takes for this to happen is given by
We can now use the second equation to determine the horizontal distance
The distance from the launch point is thus