# A projectile is shot from the ground at an angle of #(5 pi)/12 # and a speed of #4/5 m/s#. Factoring in both horizontal and vertical movement, what will the projectile's distance from the starting point be when it reaches its maximum height?

##### 1 Answer

The distance is

#### Explanation:

Resolving in the vertical direction

The initial velocity is

Applying the equation of motion

At the greatest height,

The acceleration due to gravity is

Therefore,

The greatest height is

The time to reach the greatest height is

Applying the equation of motion

The time is

Resolving in the horizontal direction

The velocity is constant and

The distance travelled in the horizontal direction is

The distance from the starting point is