# A projectile is shot from the ground at an angle of #(5 pi)/12 # and a speed of #7/15 m/s#. Factoring in both horizontal and vertical movement, what will the projectile's distance from the starting point be when it reaches its maximum height?

##### 1 Answer

Aug 11, 2017

0.0115 m (assuming

#### Explanation:

The maximum height the projectile reaches is

The horizontal distance it travels up to this point is

The distance of this point from the starting point is

#sqrt{h^2+d^2} = 0.0115 m$