A projectile is shot from the ground at an angle of #pi/4 # and a speed of #6 m/s#. Factoring in both horizontal and vertical movement, what will the projectile's distance from the starting point be when it reaches its maximum height?
Split up the velocity into its horizontal and vertical components using trigonometry,
Now you should work out the halfway point, where upwards velocity becomes
where the acceleration of gravity
Now you can work out the horizontal distance by
and the vertical distance by
The overall distance is found by Pythagoras' theorem,