Question

A projectile is shot from the ground at an angle of `pi/8` and a speed of `1 m/s`. When the projectile is at its maximum height, what will its distance from the starting point be?

Answer 1

`t=0,04" "s"`
`X=v_i*t*cos alpha=0,036 " m"`

Explanation:

`"1- elapsed time to reach its maximum height : "t=(v_i*sin alpha)/g`
`t=0,04" "s"`
`"2- "X=v_i*t*cos alpha=0,036 " m"`