# A projectile is shot from the ground at an angle of pi/8  and a speed of 1 m/s. When the projectile is at its maximum height, what will its distance from the starting point be?

$t = 0 , 04 \text{ "s}$
$X = {v}_{i} \cdot t \cdot \cos \alpha = 0 , 036 \text{ m}$
$\text{1- elapsed time to reach its maximum height : } t = \frac{{v}_{i} \cdot \sin \alpha}{g}$
$t = 0 , 04 \text{ "s}$
$\text{2- "X=v_i*t*cos alpha=0,036 " m}$