A projectile is thrown with the speed 'u' at an angle '⍬' to the horizontal. What is the radius of curvature of it's trajectory when the velocity vector of the projectile makes an angle '⍺' with the horizontal?
2 Answers
Please see the explanation below
Explanation:
The trajectory of the projectile in the
At any point
The horizontal component of the velocity is
and the vertical component is
The resultant velocity is
The angle
The centripetal acceleration is
You can also get the same result by applying the formula
Explanation:
For the motion:
-
#bb a = ((0 ),( - g ))# -
#bb v = ((u cos theta \ ),(u sin theta \ - g t ))#
And curvature:
# R= |bbv|^3/|bb v times bb a|#
#u, g, theta gt 0# #