# A punter in a football game kicks a ball from the goal 60° from the horizontal at 25 m/s. What is the hang time afthe punt, and how far down field does the ball land?

Nov 21, 2015

$\left(a\right) \text{ " 4.42"s}$

$\left(b\right) \text{ " 55.25"m}$

#### Explanation:

$\left(a\right)$

We get the time taken to reach the maximum height by using the vertical component of the velocity:

$v = u + a t$

$\therefore 0 = 25 \sin 60 - 9.8 t$

$\therefore t = \frac{61.65}{9.8} = 2.21 \text{s}$

By inference the return to earth will take the same time, assuming a level playing field.

$\therefore$ total time in flight $= 2 \times 2.21 = 4.42 \text{s}$

$\left(b\right)$

The horizontal component of velocity is constant so we get:

Distance = speed x time

$= 25 \cos 60 \times 4.42 = 55.25 \text{m}$