A pyramid has a parallelogram shaped base and a peak directly above its center. Its base's sides have lengths of $7$ $7$ and $4$ $4$ and the pyramid's height is $6$ $6$ . If one of the base's corners has an angle of $\frac{π}{3}$ $pi/3$ , what is the pyramid's surface area?

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Answer 1 · 2017-10-18T14:26:50

Lateral surface area $= 36.961$ $= 36.961$
Total surface area $= 61.2097$ $=61.2097$

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Area of base $= 24.2487$ $=24.2487$

Area of two corresponding slant sides $= 12.1559$ $=12.1559$
Area of other two slant sides $= 6.3246$ $=6.3246$

Lateral surface area $= (2 \cdot 12.1559) + (2 \cdot 6.3246) = 36.961$ $=(2*12.1559) + (2*6.3246) = 36.961$

Total surface area = lateral surface area + base area
$= 36.961 + 24.2487$ $= 36.961 + 24.2487$

Total surface area $= 61.2097$ $=61.2097$

A pyramid has a parallelogram shaped base and a peak directly above its center. Its base's sides have lengths of 7 77 and 4 44 and the pyramid's height is 6 66 . If one of the base's corners has an angle of pi/3π3pi/3, what is the pyramid's surface area?