Question

A rally car drives `85km` along a road from `A` and `B`, on a bearing `029degreesT`. The car then travels `58km` along a road to `C` on a bearing `153degreesT`?

a) What is the distance of the car from its starting point?
b) What is the bearing of the car from its starting point?

Answer 1

a) 143 km

b) 45.27˚

Explanation:

From the information given to us, the starting point is A. The total distance travelled is just adding up 85km and 58km, giving us 143km.

for part b, we are going to draw(well not me but you will). You end with a triangle that looks like

The question is asking for the angle of C.

You will use the sine rule to find the angle:

`sin(x)/85 = sin(29)/58`

Now just rearrange the equation to have sin(x) on its own:

`sinx =(sin29*85)/58`

Now take the inverse sine to calculate the angle:

`sin^-1((sin29*85)/58) = 45.27˚`