A rectangular box has a length of 8 feet and a width of 2 feet. The length of the three-dimensional diagonal is 10 feet. What is the height of the box?

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Answer 1 · 2015-11-29T15:42:04

#d=sqrt(l^2+w^2+h^2)#

If you are given the diagonal #(d)# the width and the length, then you can solve for the height #(h)# using the formula above.

#d=sqrt(l^2+w^2+h^2)#

#10=sqrt(8^2+2^2+h^2)#

Now, square both sides ...

#100=64+4+h^2#

Finally, solve for h ...

#h=sqrt(100-64-4)=sqrt(32)=4sqrt2#

hope that helped