A rectangular room is 6 meters longer than it is wide, and its perimeter is 32 meters. How do you find the dimension of the room?

2 Answers
Sep 5, 2015

Answer:

Length is 11 m.; Width is 5 m.

Explanation:

Define:
#color(white)("XX")L = " length"#
#color(white)("XX")W = " width"#

Given
#color(white)("XX")L=W+6#
#color(white)("XX")"(perimeter = " = 2(L+W) = 32#

#color(white)("XX")rarr 2((W+6)+W) = 32#

#color(white)("XX")rarr 2W+6 = 16#

#color(white)("XX")rarr W=5#

and since #L=W+6#
#color(white)("XX")rarr L=11#

Sep 5, 2015

Answer:

5m x 11m

Explanation:

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take the width of the room as #x#, then the length of the room becomes #x+6# according to the data.

i can take these data and write an equation as follows which shows the perimeter of the room

#32 = 2(x+6) + 2x#
#32 =4x+ 12#
#4x= 20#
#x= 5m# this is the width of the room

the length of the room = # 5+ 6 = 11m#

so the dimensions of the room :
5m x 11m