# A resting car starts accelerating uniformly at #a_1# rate a then moves at a constant velocity =4m/s then decelerates at a constant rate #a_2#. the velocity of the car is greater than 2m/s for 10sec. What is the distance traversed by the car?

##### 1 Answer

#### Answer:

The total distance was

#### Explanation:

The car accelerates uniformly from rest to

I will assume we need to find distance from start until the deceleration brings the car to a stop.

We are also told that the velocity was greater than

Because both

#v_"ave" = (u + v)/2

Therefore the total distance was

I hope this helps,

Steve