A rocket accelerates at a rate of #30# #m##/##s^2# for #2# minutes. What is its change in velocity?

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Answer 1 · 2018-04-30T14:22:46

Assuming the rocket is accelerating translationally in one dimension, we're given,

#a = (30"m")/"s"^2#

#t = 2"min"# (needs converted)

#nu_0 = 0#

Recall,

#nu = nu_0 + at#

Hence,

#=> Deltanu = (30"m")/"s"^2 * 2"min" * (60"s")/"min" approx (3.6*10^3"m")/"s"#

is the change in velocity of this rocket.