A rocket travelling at +88m/s is accelerated to +132m/s over a 15s interval. What is its displacement during this time?

1 Answer
Apr 8, 2018

The displacement is $= 1650 m$

Explanation:

Apply the equation of motion

$v = u + a t$

The acceleration is

$a = \frac{v - u}{t} = \frac{132 - 88}{15} = 2.93 m {s}^{-} 2$

The displacement is calculated with the equation

${v}^{2} = {u}^{2} + 2 a s$

The displacement is

$s = \frac{{v}^{2} - {u}^{2}}{2 a} = \frac{{132}^{2} - {88}^{2}}{2 \cdot 2.93} = 1650 m$