A roller coaster cart with mass m= 150 kg is at the top of a ride travelling at #v_0 = 10# m/s on frictionless tracks. The cart then descends on the almost vertical drop of the ride. The height is 110 m high. What is the cart's speed at base of the ride?

1 Answer
Nov 8, 2015

Answer:

#47.5"m/s"#

Explanation:

I will apply the conservation of energy. The sum of the kinetic and potential energy at the top of the ride will be converted into kinetic energy at the bottom:

#1/2mv_0^2+mgh=1/2mv^2#

#:.1/2xx150xx10^2+(150xx9.8xx110)=1/2xx150xxv^2#

#:.7500+161700=75v^2#

#:.v=sqrt(2256)#

#v=47.5"m/s"#