Question

A roller coaster cart with mass m= 150 kg is at the top of a ride travelling at `v_0 = 10` m/s on frictionless tracks. The cart then descends on the almost vertical drop of the ride. The height is 110 m high. What is the cart's speed at base of the ride?

Answer 1

`47.5"m/s"`

Explanation:

I will apply the conservation of energy. The sum of the kinetic and potential energy at the top of the ride will be converted into kinetic energy at the bottom:

`1/2mv_0^2+mgh=1/2mv^2`

`:.1/2xx150xx10^2+(150xx9.8xx110)=1/2xx150xxv^2`

`:.7500+161700=75v^2`

`:.v=sqrt(2256)`

`v=47.5"m/s"`