Question

A rope of length L is pulled by a constant force f. what is the tension in the Rope at a distance x from the end where the force is applied?

Answer 1

See an explanation below

Explanation:

This is also an open question.

The simplest answer (if the rope is weightless) is that according to Newton's Third Law, the

Tension is `=fN`

Suppose the diameter of the rope is `=(d)m`

The cross sectional area of the rope is `A=(pid^2/4)m^2`

Suppose the density of the material of the rope is `=(rho)kgm^-3`

Then the mass of the rope of length `xm` is

`m=(pid^2/4*x*rho) kg`

The weight of the rope is

`w=(pid^2/4*x*rho*g) N`

Where the acceleration due to gravity is `g=9.8ms^-2`

Therefore,

The tension in the rope is

`T=(f+(pid^2/4*x*rho*g)) N`