A sample of 4 different calculators is randomly selected from a group containing 16 that are defective and 30 that have no defects; what is the probability that at least one of the calculators is defective?
Apply "at least one" rule:
P( at least one ) = 1 - P( complement of 'all' )
Apply "at least one" rule:
P( at least one ) = 1 - P( complement of 'all' )
1 Answer
Jul 13, 2017
P(at least one) 0.832
Explanation:
P (at least one defective) = 1 - P(all calculators work)
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