Question

A sample of an gas has a volume of 2.25 L at 286 K and 1.13 atm. What is the pressure when the volume is 1.89 L and temperature is 302 K?

Answer 1

The combined gas law holds that `(P_1V_1)/T_1=(P_2V_2)/T_2`. The amount of gas is assumed to be constant.

Explanation:

And so `P_2=(P_1V_1T_2)/(T_1V_2).`

The RHS expression clearly has the units of pressure as required, why?

`P_2=(1.13*atmxx2.25*cancelLxx302*cancelK)/(286*cancelKxx1.89*cancelL)=??atm`