A sample of an gas has a volume of 2.25 L at 286 K and 1.13 atm. What is the pressure when the volume is 1.89 L and temperature is 302 K?

The combined gas law holds that $\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$. The amount of gas is assumed to be constant.
And so ${P}_{2} = \frac{{P}_{1} {V}_{1} {T}_{2}}{{T}_{1} {V}_{2}} .$
P_2=(1.13*atmxx2.25*cancelLxx302*cancelK)/(286*cancelKxx1.89*cancelL)=??atm