Question

A sample of an ideal gas has a volume of 2.28 L at 289 K and 1.01 atm. What is the pressure when the volume is 1.65 L and the temperature is 305 K?

Answer 1

Well, I make `P_2~=1.4*atm`

Explanation:

From the old combined gas equation for a GIVEN quantity of gas.....

`(P_1V_1)/T_1=(P_2V_2)/T_2`...

And so `P_2=(P_1V_1)/T_1xxT_2/V_2`

`=(1.01*atmxx2.28*L)/(289*K)xx(305*K)/(1.65*L)=??*atm`

Is the increase in pressure CONSISTENT with an increase in temperature, and a DECREASE in volume? Si or non....?