# A sample of an ideal gas has a volume of 2.28 L at 289 K and 1.01 atm. What is the pressure when the volume is 1.65 L and the temperature is 305 K?

Aug 5, 2018

Well, I make ${P}_{2} \cong 1.4 \cdot a t m$

#### Explanation:

From the old combined gas equation for a GIVEN quantity of gas.....

$\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$...

And so ${P}_{2} = \frac{{P}_{1} {V}_{1}}{T} _ 1 \times {T}_{2} / {V}_{2}$

=(1.01*atmxx2.28*L)/(289*K)xx(305*K)/(1.65*L)=??*atm

Is the increase in pressure CONSISTENT with an increase in temperature, and a DECREASE in volume? Si or non....?