Question

A sample of an ideal gas has a volume of 3.65 L at 14.20 °C and 1.80 atm. What is the volume of the gas at 24.80 °C and 0.993 atm?

Answer 1

The idea is to do your homework yisself...

Explanation:

You have got the Combined Gas Equation for an Ideal Gas, which holds that `(P_1V_1)/T_1=(P_2V_2)/T_2`...we solve for `V_2=(P_1xxV_1xxT_2)/(T_1xxP_2)`...

Temperature if quoted as absolute temperature...

`"Absolute temperature"="degrees Celsius + 273.15"*K`

`V_2=(1.80*atmxx3.65*Lxx298*K)/(287.4*Kxx0.993*atm)=??*L`..

Answer 2

The volume will be 6.86 L.

Explanation:

The Combined Gas Law is

`color(blue)(bar(ul(|color(white)(a/a)(p_1V_1)/T_1 = (p_2V_2)/T_2color(white)(a/a)|)))" "`

We can rearrange the equation to get

`V_2 = V_1 × p_1/p_2 × T_2/T_1`

In this problem

`p_1 = "1.80 atm"; color(white)(ll)V_1 = "3.65 L": T_1 = "(14.20 + 273.15) K = 287.35 K"`
`p_2 = "0.993 atm"; V_2 = ?; color(white)(mml)T_2 = "(24.80 + 273.15) K = 297.95 K"`

∴ `V_2 = 3.65color(red)(cancel(color(black)("L"))) × (1.80 color(red)(cancel(color(black)("atm"))))/(0.993 color(red)(cancel(color(black)("atm")))) × (297.95 color(red)(cancel(color(black)("K"))))/(287.35 color(red)(cancel(color(black)("K")))) = "6.86 L"`