A sample of gas has a volume of 250 c#m^3# at 28.5 °C and 95.9 kPa. What volume will the gas occupy at STP?

1 Answer
Nov 10, 2015

Answer:

The volume of the gas at STP will be #"0.217 L"#.

Explanation:

#"STP=273.15 K and 100 kPa"#

Use the equation from the combined gas law, #(P_1V_1)/T_1=(P_2V_2)/T_2#.

Given/Known
#P_1="95.9 kPa"#
#V_1="250 cm"^3"=250 mL"xx(1 "L")/(1000 "mL")="0.250 L"#
#T_1="28.5"^"o""C"+273.15="301.7 K"#
#P_2="100 kPa"#
#T_2="273.15 K"#

Unknown
#V_2#

Equation
#(P_1V_1)/T_1=(P_2V_2)/T_2#.

Solution
Rearrange the equation to isolate #V_2# and solve.

#V_2=(P_1V_1T_2)/(T_1P_2)#

#"V"_2=((95.9 "kPa") * (0.250"L") * (273.15"K"))/((301.7"K")*(100"kPa"))="0.217 L"#