Question

A sample of O2 under 2.00 atm occupies 550 ml at 25.0˚C. What temperature will be needed to produce a volume of 100 ml ?

Answer 1

`54.2 "K"`

Explanation:

Use `PV= nRT` to solve for `n` the number of mols `O_2`

`2 cancel"atm"* (mol cancel"K")/(0.0821 cancel"Latm")* (0.550 cancel"L")/(298 cancel"K")=0.04496 "mol O"_2`

To solve for the temperature:
`T= (PV)/(nR)`

`0.100 cancelL*(cancel"mol" K)/(0.0821 cancel"Latm")*(2cancel"atm")/(0.04496 cancel"mol")=54.2 K`