A sheet of cardboard 3 ft by 4 ft will be made into a box by cutting equal-sized squares from each corner and folding up the four edges. What will be the dimensions of the box with the largest volume?

1 Answer

#1.86 ft# x #2.86 ft# x #0.57 ft#

Explanation:

1) Draw out the picture. You will see that the height will be #x#, the width will be #3-2x#, and the length will be #4-2x#.
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2) You know the formula for volume will be V = LWH. So, you plug in the numbers you know, creating #V = x(3-2x)(4-2x)#.

3) Simplify by foiling and you get #V = 4x^3 - 14x^2 +12x#

4) Find the derivative of the equation. You get #V' = 12x^2 - 28x +12#.

5) Find the critical numbers by seeing where #V' = 0# (since V' DNE is not a possible scenario in this problem).
#4(3x^2 - 7x +3) = 0#
Use the quadratic formula or your calculator to solve for #x#
#x = 0.57, 1.77#

6) Check to see which numbers are in the domain.
#1.77# is not in the domain since that would make one of our side lengths less than zero. So our only answer is: #x = 0.57#

7) Plug x back into the equations to get the dimensions
#3-2(.57) = 1.86 ft#
#4-2(.57) = 2.86#

So, you know the dimensions are #1.86 # ft x #2.86# ft x #0.57# ft.