A shell is ﬁred from the ground with an initial speed of #1.70 x 10^3# m/s at an initial angle of 55.0° to the horizontal, Neglecting air resistance, what is the shell's horizontal range and the amount of time the shell is in motion?

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Answer 1 · 2015-11-13T14:06:46

#(a)# #277.1"km"#

#(b)# # 284.2"s"#

#(a)# The range, assuming level ground, is given by:

#d=(v^2)/(g)sin(2theta)#

#:.d=((1.7xx10^(3))^(2)xx0.9397)/(9.8)#

#d=0.2771xx10^(6)"m"#

#d=277.1"km"#

#(b)#

The horizontal component of velocity is constant and is equal to #vcostheta#.

So #t=s/v=(0.2771xx10^(6))/(1.7xx10^(3)xxcos55)#

#:.t=(277.1)/(1.7xx0.573)#

#t=284.2"s"#