A soccer ball is kicked at an angle of 45° with a speed of 20 m/s. What is the max height? How Iong does it take to reach max height? What is the hang time?

1 Answer
Junaid Mirza
Nov 5, 2017

#0.5# metres and #sqrt(2)# seconds

Explanation:

Maximum height #= (u^2sin^2theta) / (2g) = [(20 ms^-1)^2 × (1/sqrt(2))^2] / (2 × 10 ms^-2) = 0.5 m#

Time to reach maximum height #=(usintheta)/g = (20 ms^-1 × 1/sqrt(2)) / (10 ms^-2) = sqrt(2)# second

[Note: I took g = 10 m/s²]

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