# A solution contains 0.063 g of oxalic acid, H_2C_2O_4 * 2H_2O, in 250 mL. What is the molarity of this solution?

$\text{Molarity}$ $\cong$ $2 \times {10}^{-} 3 \cdot m o l \cdot {L}^{-} 1$
$\text{Molarity}$ $=$ $\text{Moles of solute"/"Volume of solution}$
$=$ $\frac{0.063 \cdot g}{126.07 \cdot g \cdot m o {l}^{-} 1} \times \frac{1}{0.250 \cdot L}$ $=$ ??*mol*L^-1