# A solution contains 72.0 g of HCl and 468 g of C_6H_6. What is the mole fraction of benzene?

Sep 15, 2016

The mole fraction of benzene is 0.752.

#### Explanation:

The mole fraction of a substance in a solution is equal to the moles of the substance divided by the total moles of all substances in the solution.

$\text{Mole fraction}$$=$$\text{mol X"/"mol X+mol Y}$

The mass of each compound needs to be converted to moles by dividing the mass by its molar mass.

First determine the molar mass of both compounds.

Molar Mass HCl:

(1xx1.008 "g/mol")+(1xx35.45 "g/mol")="36.458 g/mol"

Molar Mass $\text{C"_6"H"_6}$:

(6xx12.011"g/mol")+(6xx1.008"g/mol")="78.114 g/mol"

Next determine the moles present for each compound by dividing the mass given in the question by its molar mass.

Moles HCl:

$\text{72.0 g HCl"xx"1 mol HCl"/"36.458 g HCl"="1.974 mol HCl}$

Moles $\text{C"_6"H"_6} :$

$\text{468 g C"_6"H"_6xx("1 mol C"_6"H"_6)/("78.114 g C"_6"H"_6)="5.991 mol C"_6"H"_6}$

Determine the Mole Fraction of Benzene

$\text{C"_6"H"_6}$$\Rightarrow$$\text{5.991"/"5.991+1.974"="0.752}$