A solution is prepared from 8 grams of acetic acid (#CH_2CO_2H#) and 725 grams of water. What is the molarity of this solution?

1 Answer
Aug 15, 2016

Answer:

#"Molarity"# #=# #"Moles of solute"/"Volume of solution"#

Explanation:

#"Molarity"# #=# #((8*g)/(60.05*g*mol^-1))/(0.725*L)# #~=# #0.18*mol*L^-1#.

Note that I have assumed here that the volume of the acid in the given mass of water is not going to vary substantially from #0.725*L#, which was the standard volume of the mass of water used to dilute it. This is a reasonable assumption.

If we liked, we could calculate the #"molality"# of the solution:

#"Moles of solute"/"kg of solvent"#.