A spring with a constant of 3 (kg)/(s^2) is lying on the ground with one end attached to a wall. An object with a mass of 5 kg and speed of 7 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?

1 Answer
Feb 5, 2016

Delta x=7 . sqrt(5/3) m

Explanation:

"energy on object is :" E_k=1/2.m. v^2
E_k= 1/2 . 5 .7^2
E_k=1/2 . 5. 49
"energy on spring :"E_p=1/2 . k . Delta x^2
E_k=E_P
cancel(1/2) .5 .49=cancel(1/2) .3 .Delta x^2
Delta x^2=5.49/3
Delta x=7 . sqrt(5/3) m