A spring with a constant of $6 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $3 kg$ and speed of $2 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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A spring with a constant of $6 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $3 kg$ and speed of $2 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2016-02-04T19:34:48

$Delta x=sqrt2$ m

Explanation:

$"Kinetics Energy of the object is:"$
$E_k=1/2*m*v^2$
$E_k=1/2*3*2^2$
$E_k=6J$
$E_k " transfers to the spring"$
$E_p=1/2*6*Delta x^2$
$cancel(6)=1/2*cancel(6)* Delta x^2$
$2=Delta x^2$
$Delta x=sqrt2$ m

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A spring with a constant of $6 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $3 kg$ and speed of $2 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

1 Answer

Explanation:

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A spring with a constant of 6 (kg)/s^26 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 3 kg3 kg and speed of 2 m/s2 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?

1 Answer

Explanation:

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A spring with a constant of $6 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $3 kg$ and speed of $2 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?