# A spring with a constant of 8 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 7 kg and speed of 9 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?

Feb 13, 2016

KE = $\frac{1}{2} m {v}^{2}$ where m = mass and v = velocity
PE stored in the spring = $\frac{1}{2} k {x}^{2}$ where x = compression and k force constant
The compression of spring,x= sqrt(mv^2/k = $\sqrt{7 \cdot {9}^{2} / 8}$ =8.42 m