A stretched wire of length 0.5 m vibrates at the fundamental frequency 250 Hz. The tension in the wire is 35 N. Calculate the mass per unit length. Give your answer in g/m.?

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Answer 1 · 2018-02-20T07:28:10

The mass per unit length is #=0.56gm^-1#

Apply Mersenne's Laws

The fundamental frequency of a vibrating string is

#f_0=1/(2L)sqrt(T/mu)#

The fundamental frequancy is #f_0=250Hz#

The length of the wire is #L=0.5m#

The tension in the wire is #T=35N#

The mass per unit length is #mu#

#T/mu=4f_0^2L^2#

#mu=T/(4f_0^2L^2)=35/(4*250^2*0.5^2)=0.00056kgm^-1#

The mass per unit length is #=0.56gm^-1#