# A substance has an empirical formula of CH_2 and a molar mass of 56 grams per mole. What is the molecular formula for this compound?

Jan 3, 2017

## The molecular formula is always a whole number multiple of the empirical formula, so.........

#### Explanation:

("empirical formula")xxn="Molecular formula",

i.e. $\left(12.01 + 2 \times 1.00794\right) \cdot g \cdot m o {l}^{-} 1 \times n = 56 \cdot g \cdot m o {l}^{-} 1$

$n = \frac{56 \cdot g \cdot m o {l}^{-} 1}{\left(12.01 + 2 \times 1.00794\right) \cdot g \cdot m o {l}^{-} 1}$

And clearly, $n = 4$.

So $\text{molecular formula}$ $=$ ${\left(C {H}_{2}\right)}_{4}$

$= {C}_{4} {H}_{8}$

The stuff is a butylene OR a three-membered or four-membered ring.