A swimming pool can be filled by an inlet pipe in 3 hours. It can be drained by a drainpipe in 6 hours. By mistake, both pipes are opened at the same time. If the pool is empty, in how many hours will it be filled?

2 Answers
Mar 4, 2017

#6# hours

Explanation:

Gross input rate: #(1" tank")/(3" hours")#

Gross output rate: #(1 " tank")/(6" hours")#

Net (input) rate: #(1" tank")/(3" hours")-(1" tank")/(6" hours")#

#color(white)("XXXXXXXX")=(1" tank")/(6" hours")color(white)("XXX")# (since #1/3-1/6=1/6#)

#rArr # It will take #6# hours to fill #1# tank

Mar 4, 2017

#6# hours to fill.

Explanation:

Let's consider what happens in one hour.

If a pool fills in 3 hours, it means that after 1 hour it is #1/3# full.

If a pool empties in 6 hours, it means that in 1 hour it loses #1/6#

So if it is filling and draining at the same time, after one hour the difference would be:

#1/3-1/6 = 1/6#

The nett result is that the pool fills at a rate of #1/6# per hour.

#1 div 1/6 = 6# hours to fill.