A transverse wave is described by equation y=y_0sin2pi(ft-x/lambda)....The maximum velocity of particle will be 4times of velocity of wave provided...If lamda equals to?

1 Answer
Jun 2, 2017

A transverse wave is described by equation

y=y_0sin2pi(ft-x/lambda)

The maximum velocity of particle will be

v_"max"="amplitude"xx2pif=y_0xx2pif

Velocity of wave v_"wave"=lamdaxxf

By the condition of the problem

v_"max"=4xx v_"wave"

=>y_0xx2pif=4xx lamdaxxf

=>lambda=(piy_0)/2