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A triangle has corners at #(1, 4 )#, #( 2, 3 )#, and #( 5 , 2 )#. If the triangle is dilated by # 3 x# around #(1, 1)#, what will the new coordinates of its corners be?

1 Answer
Feb 28, 2018

Answer:

#(1, 9x +1), (3x + 1, 6x+1), (12x+1, 3x+1)#

Explanation:

Let's shift the expansion to be around the origin. Hence, the corners become #(0, 3), (1, 2), (4, 1)#. We do this because expanding around the origin is really easy. We just multiply everything by that value.

Therefore, the expansion of these new points is #(0, 9x),(3x, 6x),(12x, 3x) #

Returning them around (1,1), we get the final solution:
#(1, 9x +1), (3x + 1, 6x+1), (12x+1, 3x+1)#