A triangle has corners at (1, 7 ), ( 8, 3 ), and ( 4 , 8 ). If the triangle is dilated by 2 x around (2, 5), what will the new coordinates of its corners be?
1 Answer
Feb 17, 2018
Explanation:
"label the vertices of the triangle"
A(1,7),B(8,3)" and "C(4,8)
"and A', B', C' the images of A, B and C"
"let the centre of dilatation be "D(2,5)
rArrvec(DA')=color(red)(2)vec(DA)
rArrula'-uld=2(ula-uld)=2ula-2uld
rArrula'=2ula-uld
color(white)(rArrula')=2((1),(7))-((2),(5))=((0),(9))
"the coordinates of A' are the components of "ula'
rArrA'=(0,9)
"similarly "
vec(DB')=color(red)(2)vec(DB)
rArrulb'=2ulb-uld
color(white)(rArrulb')=2((8),(3))-((2),(5))=((14),(1))
rArrB'=(14,1)
"and "vec(DC')=color(red)(2)vec(DC)
rArrulc'=2ulc-uld
color(white)(rArrulc')=2((4),(8))-((2),(5))=((6),(11))
rArrC'=(6,11)
color(blue)"Result after dilatation"
(1,7)to(0,9),(8,3)to(14,1),(4,8)to(6,11)