Question

A triangle has corners at `(2 ,4 )`, `(8 ,6 )`, and `(7 ,9 )`. How far is the triangle's centroid from the origin?

Answer 1

The distance is `sqrt(650)/3`

Explanation:

Let point O = the centroid = `(O_x, O_y)`

`O_x = (2 + 8 + 7)/3 = 17/3`

`O_y = (4 + 6 + 9)/3 = 19/3`

The distance, d, from the origin is:

`d = sqrt((17/3 - 0)^2 + (19/3 - 0)^2) = sqrt(650)/3`