A triangle has corners at $(2, 7)$ $(2, 7 )$ , ( 5, -2) $, and$ $, and$ ( 1, -1)#. If the triangle is reflected across the x-axis, what will its new centroid be?

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A triangle has corners at $(2, 7)$ $(2, 7 )$ , ( 5, -2) $, and$ $, and$ ( 1, -1)#. If the triangle is reflected across the x-axis, what will its new centroid be?

1 Answer

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Answer 1 · 2016-03-07T07:58:07

The new centroid $(\frac{8}{3}, - \frac{4}{3})$ $(8/3, -4/3)$

Explanation:

From the old centroid :(8/3, 4/3)

$x = \frac{x_{1} + x_{2} + x_{3}}{3} = \frac{1 + 2 + 5}{3} = \frac{8}{3}$ $x=(x_1+x_2+x_3)/3=(1+2+5)/3=8/3$
$y = \frac{y_{1} + y_{2} + y_{3}}{3} = \frac{- 1 + 7 - 2}{3} = \frac{4}{3}$ $y=(y_1+y_2+y_3)/3=(-1+7-2)/3=4/3$

Only the ordinate 4/3 will change to -4/3 located at the 4th quadrant.
So the new centroid is $(\frac{8}{3}, - \frac{4}{3})$ $(8/3, -4/3)$

God bless...I hope the explanation is useful.

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A triangle has corners at $(2, 7)$ $(2, 7 )$ , ( 5, -2) $, and$ $, and$ ( 1, -1)#. If the triangle is reflected across the x-axis, what will its new centroid be?

1 Answer

Explanation:

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1 Answer

Explanation:

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A triangle has corners at $(2, 7)$ $(2, 7 )$ , ( 5, -2) $, and$ $, and$ ( 1, -1)#. If the triangle is reflected across the x-axis, what will its new centroid be?