# A triangle has corners at (4 ,7 ), (2 ,6 ), and (3 ,8 ). How far is the triangle's centroid from the origin?

Oct 15, 2016

The distance from the origin is $\sqrt{58}$

#### Explanation:

Let O = the centroid point, $\left({O}_{x} , {O}_{y}\right)$

${O}_{x} = \frac{4 + 2 + 3}{3} = 3$

${O}_{y} = \frac{7 + 6 + 8}{3} = 7$

The distance, d, from the origin is:

$d = \sqrt{{\left(3 - 0\right)}^{2} + {\left(7 - 0\right)}^{2}}$

$d = \sqrt{58}$