# A triangle has corners at (6 ,9 ), (5 ,7 ), and (3 ,8 ). How far is the triangle's centroid from the origin?

The distance of centroid from origin(0,0) is $9.26 \left(2 \mathrm{dp}\right)$unit
The co ordinate of centroid is $\frac{6 + 5 + 3}{3} , \frac{9 + 7 + 8}{3} \mathmr{and} \left(\frac{14}{3} , 8\right)$
The distance of centroid from origin(0,0) is $d = \sqrt{{\left(\frac{14}{3} - 0\right)}^{2} + {\left(8 - 0\right)}^{2}} = \sqrt{\frac{196}{9} + 64} = 9.26 \left(2 \mathrm{dp}\right)$unit[Ans]