Question

A triangle has corners at `(7 ,2 )`, `(6 ,7 )`, and `(3 ,5 )`. How far is the triangle's centroid from the origin?

Answer 1

The centriod is the average of the coordinates:

`C=( {7+6+3}/3, {2+7+5}/3) = (16/3, 14/3)`

so its distance to the origin is

`\sqrt{(16/3)^2 + (14/3)^2}=sqrt{ (2/3)^2(8^2+7^2) } = 2/3 sqrt{113}`