# A triangle has corners at (9 ,4 ), (2 ,6 ), and (5 ,8 ). How far is the triangle's centroid from the origin?

Distance of centroid from the origin is $8.03$ units
The co ordinates of centroid of triangle is x=(x_1+x_2+x_3)/3=(9+2+5)/3=16/3 ; y=(y_1+y_2+y_3)/3=(4+6+8)/3=18/3=6i.e$\left(\frac{16}{3} , 6\right)$.Distance of centroid from the origin is $\sqrt{{\left(\frac{16}{3} - 0\right)}^{2} + {\left(6 - 0\right)}^{2}} = 8.03$ units [Ans]