A triangle has corners points A, B, and C. Side AB has a length of #9 #. The distance between the intersection of point A's angle bisector with side BC and point B is #6 #. If side AC has a length of #10 #, what is the length of side BC?

1 Answer

Side #BC=12 2/3=12.6666" "#units

Explanation:

There is a theorem in Geometry which states ,"An angle bisector of an angle of a triangle divides the opposite side in two segments that are proportional to the other two sides of the triangle."

Let the intersection be point #I#

Therefore, our equation is as follows
#AB:IB=AC:IC#

#(AB)/(IB)=(AC)/(IC)#

#9/6=10/(IC)#

#IC=(6(10))/9#

#IC=20/3#

The length of #BC=IB+IC#

#BC=6+20/3#

#BC=38/3=12 2/3#

God bless...I hope the explanation is useful.