# A truck 10,000 kg going 40 m/s loses its brakes. If the runoff ramp is at an angle of 30°, how long will it take to stop?

Nov 22, 2015

$2.04 \text{s}$

#### Explanation:

I'm assuming that the engine is cut off at the point it hits the ramp.

Considering the vertical component of the truck's velocity:

$v = u + a t$

$\therefore 0 = 40 \sin 30 - 9.8 t$

$t = \frac{20}{9.8} = 2.04 \text{s}$

The mass is irrelevant.