A vendor sells hot dogs, chips, and drinks. a customer buys 2 hot dogs, 5 chips, and 2 drinks for 10.50. the price of 1 hot dog is $0.50 more than price of 1 chips. 1 drink is $1.75 less than the price of 2 hot dogs. How do you find the cost of each item?

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Answer 1 · 2015-09-28T16:30:06

I found:
hot dogs: $1.5$ $1.5$
chips: $$ 1$ $$1$
drinks: $$ 1.25$ $$1.25$

Call the prices of hot dogs $h$ $h$ . chips $c$ $c$ and drinks $d$ $d$ ; so:
${(2h+5c+2d=10.50),(h=c+0.5),(d=2h-1.75):}$

use the last two into the first:

$2(c+0.5)+5c+2[2(c+0.5)-1.75]=10.5$
$2c+1+5c+2[2c+1-1.75]=10.5$
$7c+1+4c-1.5=10.5$
$11c=11$
$c=11/11=$1$

into the second equation:
$h=1+0.5=$1.5$

and into the third:
$d=2*1.5-1.75=$1.25$