A waxed paper capacitor has two parallel plates, each of effective area $800 cm^$ 2. If the capacitance of the capacitor is $4425 pF$ , what is the effective thickness of the paper? The relative permittivity of the paper is 2.5.

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Answer 1 · 2018-01-18T10:56:24

0.386 mm

$sf(C=(kepsilon_0A)/d)$

$:.$ $sf(d=(kepsilon_0A)/C)$

$sf(d=(2.5xx8.55xxcancel(10^(-12))xx0.08)/(4425xxcancel(10^(-12)))color(white)(x)m)$

$sf(d=3.864xx10^(-4)color(white)(x)m)$

$sf(d=0.386color(white)(x)mm)$

A waxed paper capacitor has two parallel plates, each of effective area 800 cm^800 cm^2. If the capacitance of the capacitor is 4425 pF4425 pF, what is the effective thickness of the paper? The relative permittivity of the paper is 2.5.